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Old 11-18-2002, 10:13 PM   #14
uiuc240
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</span><table border="0" align="center" width="95%" cellpadding="3" cellspacing="1"><tr><td>Quote </td></tr><tr><td id="QUOTE">Well, you forgot to put the efficiency in the equation &nbsp;I got 254 and used .85 efficiency and 7000 rpm.
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I used .85 for the VE and an rpm of 6500...the rpm was the difference. &nbsp;I forgot the KA24DE has a rev limit at 6900...sorry.

</span><table border="0" align="center" width="95%" cellpadding="3" cellspacing="1"><tr><td>Quote </td></tr><tr><td id="QUOTE">Well, i just got my book back and went into reading. It said that if i'm not running the i/c, my compressor efficiency got to be above 60%. With the t3 "60" i'm gonna be in the 70% area, so i guess i'm fine. From what i calculated at 70% efficiency i'll be providing air of about 165*F to the intake manifold at 4 psi. Is that fine/reasonable?
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That doesn't sound too bad. &nbsp;But why not just get a Starion IC or something? &nbsp;If you're having piping made, plumbing that in won't be that hard. &nbsp;Or get an SMIC from someone with an SR (like me <img src="#/f/iB_html/non-cgi/emoticons/wink.gif" border="0" valign="absmiddle" alt=''> ).

</span><table border="0" align="center" width="95%" cellpadding="3" cellspacing="1"><tr><td>Quote </td></tr><tr><td id="QUOTE">Now i've gone back to calculate where will i hit full boost. I assumed about 3000rpm and it came out that i will need 107CFM (7.38lbs/min) of flow. Plotting that against the graph - still in the 70% area. So i guess i'm set. I'll be out of the 70% efficiency area only at 14lbs/min => 203CFM => ~5653RPM. And thats about 100-200 rpm after most people shift.
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Sounds like you've got a nice match there.

</span><table border="0" align="center" width="95%" cellpadding="3" cellspacing="1"><tr><td>Quote </td></tr><tr><td id="QUOTE">Also, what does the lower bound of the compressor map mean. Suppose, i run like 2psi of boost - 1.13 ratio. That is below the compressor map completely. What will happen? Will the turbo just never spin up to produce any valuable boost?</td></tr></table><span id='postcolor'>

I'm not sure about that. &nbsp;You're probably right that it would never make boost. &nbsp;Check out this website: turbo site &nbsp;<img src="#/f/iB_html/non-cgi/emoticons/crazy.gif" border="0" valign="absmiddle" alt=':crazy:'> &nbsp;<img src="#/f/iB_html/non-cgi/emoticons/crazy.gif" border="0" valign="absmiddle" alt=':crazy:'>

</span><table border="0" align="center" width="95%" cellpadding="3" cellspacing="1"><tr><td>Quote </td></tr><tr><td id="QUOTE">Also, the numbers on the compressor maps (t3 "60" in this case) - like 56,400 , 78,800 etc - are these the rpms of the turbo? If so, that means that the turbo won't be boosting till it spools to 56400 right?
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Yes, those are impeller rpm numbers. &nbsp;I would assume that until it reaches this point, you will not build boost. &nbsp;But, again, not sure...

</span><table border="0" align="center" width="95%" cellpadding="3" cellspacing="1"><tr><td>Quote </td></tr><tr><td id="QUOTE">Another question - the compressor efficiency means (ideal temp rise)/(actual temp rise). Suppose now the pressure ratio of 1.6 on a t3 "60" compressor map. How come the tempreture while flowing 7lbs/min is hotter than when flowing 15CFM when the turbo is supposed to spin faster. How does this work?
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Well, if you just take a quick look at the map, you'll see that this is outside the prime efficiency range of this turbo. &nbsp;It's create unnecessary backpressure and not working where it wants to work. &nbsp;Sort of like that unhappy sound your engine makes when you lug it in 5th at 1500rpm. &nbsp;<img src="#/f/iB_html/non-cgi/emoticons/smile.gif" border="0" valign="absmiddle" alt=''>

</span><table border="0" align="center" width="95%" cellpadding="3" cellspacing="1"><tr><td>Quote </td></tr><tr><td id="QUOTE">Finally, what does the trim stand for? Like what is "60" trim? Is this the a/r ratio? Like .60 => "60" trim or something? If not, is there a way to determine trim from the a/r ratio?</td></tr></table><span id='postcolor'>

Trim is the ratio of the inducer to the exducer (small to big radius of the impeller). &nbsp;A/R relates to the area of the housing. &nbsp;Umm...I think. &nbsp;Don't quote me on that.

I'm still learning too.

Eric
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