Well, you forgot to put the efficiency in the equation <img src="#/f/iB_html/non-cgi/emoticons/smile.gif" border="0" valign="absmiddle" alt='
'> I got 254 and used .85 efficiency and 7000 rpm.
Well, i just got my book back and went into reading. It said that if i'm not running the i/c, my compressor efficiency got to be above 60%. With the t3 "60" i'm gonna be in the 70% area, so i guess i'm fine. From what i calculated at 70% efficiency i'll be providing air of about 165*F to the intake manifold at 4 psi. Is that fine/reasonable?
Now i've gone back to calculate where will i hit full boost. I assumed about 3000rpm and it came out that i will need 107CFM (7.38lbs/min) of flow. Plotting that against the graph - still in the 70% area. So i guess i'm set. I'll be out of the 70% efficiency area only at 14lbs/min => 203CFM => ~5653RPM. And thats about 100-200 rpm after most people shift.
Also, what does the lower bound of the compressor map mean. Suppose, i run like 2psi of boost - 1.13 ratio. That is below the compressor map completely. What will happen? Will the turbo just never spin up to produce any valuable boost?
Also, the numbers on the compressor maps (t3 "60" in this case) - like 56,400 , 78,800 etc - are these the rpms of the turbo? If so, that means that the turbo won't be boosting till it spools to 56400 right?
Another question - the compressor efficiency means (ideal temp rise)/(actual temp rise). Suppose now the pressure ratio of 1.6 on a t3 "60" compressor map. How come the tempreture while flowing 7lbs/min is hotter than when flowing 15CFM when the turbo is supposed to spin faster. How does this work?
Finally, what does the trim stand for? Like what is "60" trim? Is this the a/r ratio? Like .60 => "60" trim or something? If not, is there a way to determine trim from the a/r ratio?